How Anyone can be a Hands-On Spherical Earth Affirmer – A Global Call to Action
VERY STRONG
EXPERIMENTAL EVIDENCE AFFIRMING THE SPHERICITY OF THE EARTH
A fairly
common story from flat earth advocates is that they started out thinking that
the earth being flat was a ridiculous idea, so they started trying to prove
that the earth was a sphere, and since they were not able to do that as easily
as they thought they should, at some point they gave up and concluded that the
earth must therefore be flat. I know there is more to their overall spiel, but
this is a significant part of what a lot of them say.
Well, I have
gotten to the point where I feel that I have proved that the earth is a sphere,
at least to my own personal and professional satisfaction. That does not mean
that I have refuted every single flat earth argument, nor have I done
experiments in all possible areas that might bear upon the issue. But I have
done enough experiments and analysis that I do feel at peace knowing with
confidence of the fact that the earth is a sphere. And I want to share with
people all over the world how they can do simple experiments right where they
live to verify for themselves that the earth is a sphere.
I welcome
anyone to comment on this presentation as well as any of my other blog posts.
Flat earth advocates, I challenge you to show me where I have made any errors
in math, science, or logic.
SURFACE OF A
SPHERICAL EARTH VS THAT OF A FLAT CIRCULAR DISK EARTH - CONCLUSIONS FROM
INDISPUTABLE DIFFERENCES IN GEOMETRICAL PROPERTIES
The basic
idea is that the geometrical properties of the surface of a sphere are very
different than the geometrical properties of the surface of a flat circular
disk. The spherical earth is laid out in terms of a defined grid of latitude
and longitude. Any point on the surface of the earth can be uniquely specified
by its coordinates of latitude and longitude. The azimuthal equidistant map is
in reality just a projection of the spherical earth onto a circular disk. So
the defined grid on this map of latitude and longitude is equivalent to that of
the spherical earth map, with one exception. The nature of the projection
causes the south pole, a point on the spherical surface of the earth, to
project into a circle, the outer boundary of the azimuthal equidistant map.
Flat earth advocates often present the azimuthal equidistant map as a flat
earth map with the north pole at the center of the circular disk and the south
“pole” not as a pole or single point, but as an outer boundary of the commonly
known earth. But when people point out the obvious problems with this map in
terms of giving unrealistic distances between points on the map, flat earth
advocates often say that they know there are problems, and they are still
working on getting an accurate flat earth map.
The
azimuthal equidistant map is an accurate map of the spherical earth, where the
map happens to be flat. But it must be interpreted properly to be useful. For
example, any straight line distances between points that run exactly north
south will scale properly. But any straight line distances between points that
deviate at all from running north south will not scale properly. This is why
when one tries to interpret the azimuthal equidistant map as a map of an actual
flat earth, in which case the distances should scale properly in any and all
directions, a distance between Perth Australia and Sydney Australia of around
5000 miles is determined when in reality we know the distance between these
cities to be around 2000 miles.
Since the
earth is really a sphere, there is no way that flat earth advocates will ever
be able to tell you where anything is on the flat earth map in a way that all
the distances will scale properly with reality. It seems clear that they
maintain that the north pole is at the center of the circular disk and that the
south “pole” is at the outer ring or boundary, and the equator is a circle half
way between the north pole and the southern ring, but once they put that stuff
on the map, why can’t they put the rest of the stuff on the map? The more that
they try to put on the flat earth map, the more it exposes the flaws in this
flat earth theory.
Even
locating the equator exposes a fatal contradiction in their flat earth
model. For the real distance around the
equator on the real spherical earth is around 25,000 miles whereas the distance
around the flat earth map’s equator is around 39,000 miles.
This and
other implications of Flat Earth Science poses many contradictions with our
world’s sophisticated system of weights and measures, geography, navigation,
science, and commerce, that has taken civilization hundreds if not thousands of
years to perfect to the very high level of precision and accuracy that has
provided many benefits to humanity, but unfortunately has also been used in
destructive and evil endeavors.
Countless
examples could be found, but here I offer just one. In 1986 the aircraft
Voyager set a record of flying around the world non-stop without having to re-fuel.
They stayed pretty close to the equator for most of the trip except for when
they took off from Edwards AFB in California and headed towards Hawaii, and
upon return came up through Mexico back to their starting point in California.
So the actual distance traveled by this plane was around 25,000 miles, but if
the same route was done on a flat earth map the distance would have been over
34,000 miles. So their average speed reported as around 115 mph should have
been over 156 mph. But wouldn’t the pilots have noticed this on their
airplane’s airspeed indicator? So according to flat earth science this record
needs to be revised, for it is a much more impressive accomplishment on the
flat earth than on the spherical earth. Just think of the many other world
records that will now need to be revised due to the proper application of flat
earth science.
DO YOUR OWN TESTS
AND YOU TOO CAN BECOME A HANDS-ON SPHERICAL EARTH AFFIRMER
But anyone
can do their own simple experiments right where they live to verify that the
readings conform to reality on the spherical earth model, but not on the flat
earth model. I have done this for where I live in San Jose, California.
Basically
what you do is drive your car a few miles between defined coordinate points on
a road that runs west east and measure the distance with your car’s odometer.
And then you do the same for a road that runs south north. From this data you
can calculate the gradients, the west east gradient and the south north
gradient, in terms of miles traveled per degree of longitude and miles traveled
per degree of latitude, respectively.
Here’s the
applicable equations that tell you what these gradients should be wherever you
are on the spherical earth or the flat earth.
Spherical
Distance
traveled/degree of longitude = (2*PI*Re*COS(latitude*(PI/180)))/360
Distance
traveled/degree of latitude = (2*PI*Re)/360
Flat
Distance
traveled/degree of longitude = ((90-latitude)/(90*360))*PI^2*Re
Distance
traveled/degree of latitude = (2*PI*Re)/360
Where Re is
the average radius of the spherical earth = 3958.755 miles, PI = 3.14159, and
latitude is in degrees as usual.
However you
got your coordinates of latitude and longitude for the points you traveled
between, if you don’t trust these values and want to do some more checking on
this, you can do the following. Go to any of several online sun calculators
that will give you the time of solar noon where you are and also at some other
place east or west of you and then verify that you get a difference in time of
4 minutes per degree of longitude. This is data that flat earth scientists
should find very hard to dispute, because anyone can measure the difference in
time for solar noon between two places. The data will be the same for all, no
matter what their views on the shape of the earth are. So this should allow you
to see if your longitude values you used for the points to determine your west
east gradient make sense for where you live. For a check on latitude values you
can check the sun angle for where you are at solar noon with the sun angle at a
place either north or south of you and see if this makes sense. I am not going
to go into the details of this here, as there is less potential for dispute
here, because this is a case where the flat earth model and the spherical earth
model happen to agree with each other. That is, on the south north gradient of
miles traveled per degree of latitude, the value is a constant of 69.0933 miles
per degree of latitude no matter where you are on either the spherical earth
map or the flat earth map.
So basically
what I did for where I live in San Jose is that back on the equinox of
September 23, 2017 I verified the sun’s angle at solar noon and determined that
it was indeed consistent with my latitude here. I took odometer readings with
my car between defined points on both a west east road and a south north road,
and calculated the gradients and found them to be consistent with what the
spherical earth model would predict.
So based on
the results I got I would have to be around 500 miles further north on a flat
earth map in order for the results to be consistent with the flat earth model,
somewhere around Sisters, Oregon on the spherical earth map.
If where you
are, it is difficult to find roads that run close to south north or west east,
just find the closest to that ideal and then correct the odometer reading from
your car by multiplying by the cosine of the angle of deviation from the ideal
path to the actual path to get the correct distance to use for calculating the
gradients.
DETAILS OF
THE DATA AND CALCULATIONS THAT I DID
Traveling
from west to east was from 37.322909, -122.010161 to 37.323274,
-121.937518. The odometer in my car said
I had gone 4.1 miles. Notice that the
latitudes of the two points are within 3 significant figures to the right of
the decimal point to each other which is sufficient to establish that for
practical purposes the points are east-west of each other. So calculating miles traveled per degree
longitude = 4.1/(122.010161-121.937518) = 56.4 miles/degree longitude. Notice that since the odometer reading of 4.1
has only 2 significant figures, the result is only good to 2 significant
figures, so it could be reported as 56
+/- 1 miles/degree
longitude. Based on the spherical earth
model the calculation is (2*PI*Rearth*COS(latitude*(PI/180)))/360 = 54.95
miles/degree longitude. So the
experimentally determined value of 56
+/-1 is consistent with the
spherical earth theoretical value of 54.95 within experimental uncertainty.
Traveling
from south to north was from 37.321039, -122.014123 to 37.362467,
-122.014167. The odometer in my car said
I had gone 2.9 miles. Notice that the
longitudes of the two points are within 3 significant figures to the right of
the decimal point to each other which is sufficient to establish that for
practical purposes the points are north-south of each other. So calculating miles traveled per degree
latitude = 2.9/(37.362467-37.321039) = 70.0 miles/degree latitude. Notice that since the odometer reading of 2.9
has only 2 significant figures, the result is only good to 2 significant
figures, so it could be reported as 70
+/- 1 miles/degree latitude. Based on the spherical earth model the
calculation is (2*PI*Rearth)/360 = 69.1 miles/degree latitude. So the experimentally determined value of
70 +/-1
is consistent with both the spherical and flat earth theoretical values,
which are the same, of 69.1 within experimental uncertainty
It is worth
noting that in both cases above the experimentally determined number was a
little greater than the theoretically calculated number. This could be due to the deviation of the
actual path driven from a perfectly straight line.
According
the flat earth geometry, you would need to be at about latitude 44.5 degrees to
get a west east gradient of 54.9 miles per degree of longitude. The calculation
is grad= ((90-latitude)/(90*360))*PI^2*Re = ((90-44.5)/(90*360))*3.14159^2*3958.755
= 54.9 miles per degree of longitude. So you would need to be at 44.5 degrees
latitude on the flat earth map, where at this latitude on the spherical earth
map you would be up right around Sisters, Oregon, if I keep the longitude the
same as San Jose.
A CALL TO
ACTION
Others all
over the world could do similar measurements and calculations as I have done
and determine if the results they get are consistent with the spherical earth
map.
Remarkably,
on the spherical earth the maximum west east gradient occurs at the equator
with a value of 69.0933. But on the flat earth map you have to go up to 32.7
degrees latitude to get this same gradient, which would be right around the
latitude of Yuma, Arizona on the spherical earth map. On the flat earth map,
the gradient is 108.5 at the equator, and once you get down to the southern
ring, the gradient is 217. In contrast, at the south pole of the spherical map
the gradient is zero.
Ask any flat
earth advocate to name one city on the earth where the west east gradient is
greater than 100 miles per degree of longitude. There should be many according
to flat earth theory, but they cannot even name one.
So much more
can be said and further experiments done on this.
Flat earth
advocates claim that GPS is not valid and it is not based on satellites, which
they claim do not exist. Well, if you start doing experiments with GPS you will
find that it is extremely accurate and also its results, when combined and
compared with independent and complementary data, are consistent with the
reality of a spherical earth.
Flat earth
advocates will say something like, GPS is based on spherical earth geometry so
that is why it works. But there is a problem with their logic. They are
essentially saying that the spherical earth map is a projection of the real
flat earth onto a sphere. Well, if that is the case, why can’t they provide a
flat earth map that works giving us where things are on that map? They can’t.
It is impossible. GPS can easily be shown to be consistent with a real
spherical earth and its map when GPS experiments are done where trips are
tracked with GPS combined with independent distance measurement methods, such
as with a car’s odometer.
I am already
working on these things and will report on the results in future posts.
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